If the pair of lines `sqrt(3)x^2-4x y+sqrt(3)y^2=0` is rotated about the origin by `pi/6` in the anticlockwise sense, then find the equation of the pair in the new position.

The pair of lines sqrt3x^(2)-4xy+sqrt3y^(2)=0 are rotated about the origin by pi//6 in anticlockwise sense. The equation of the pair in the new position, is

If the pair of straight lines ax^(2)+2hxy+by^(2)=0 is rotated about the origin through 90^(0), then find the equations in the new position.

If the pair of straight lines ax^(2)+2hxy+by^(2)=0 is rotated about the origin 90^(@); then find the eqution in the new position.

The line 2x-y=3 is rotated through an angle (pi)/(4) in anticlockwise direction about the point (2,1) ,then equation of line in its new position

If the pair of straight lines ax^(2)+2hxy+by^(2)=0 is rotated about the origin through 90^(@) , then their equations in the new position are givne by

A line x-y+1=0 cuts the y-axis at A. This line is rotated about A in the clockwise direction through 75^(@). Find the equation of the line in the new position (A) sqrt(y)+x=sqrt(3) (B) sqrt(x)+y=sqrt(3)(C)x+sqrt(y)=1(D)sqrt(x)+y=1

if the axes are rotated through 60 in the anticlockwise sense,find the transformed form of the equation x^(2)-y^(2)=a^(2)

If the represented by the equation 3y^2-x^2+2sqrt(3)x-3=0 are rotated about the point (sqrt(3),0) through an angle of 15^0 , on in clockwise direction and the other in anticlockwise direction, so that they become perpendicular, then the equation of the pair of lines in the new position is (1) y^2-x^2+2sqrt(3)x+3=0 (2) y^2-x^2+2sqrt(3)x-3=0 (3) y^2-x^2-2sqrt(3)x+3=0 (4) y^2-x^2+3=0