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Two sides `AB` and `BC` and median `AM` of one triangle ABC are respectively equal to side `PQ` and `QR` and median `PN` of `DeltaA B C~=DeltaP Q R`(see Fig. 7.40). Show that:
(i) `DeltaA B M~=DeltaP Q N`
(ii) `DeltaA B C~=DeltaP Q R`

Text Solution

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In `ΔABC`, AM is the median to BC.
∴ `BM = 1/2 BC`
In `ΔPQR`, PN is the median to QR. ...
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