A radioactiev nuleus `X` deays to a stable nuleus `Y`. Then, time graph of rate of formation of `Y` against time `t` will be:

The radioactive nucleus of an element X decays to a stable nucleus of element Y.A graph of the rate of romation of Y against time would look like:

A radioactive isotope X decays into a stable nucleus Y. Draw graphs showing the variation of rate of formation of Y versus time and the variation of population of Y versus time. Initial population of Y is zero.

If decompositon reaction A(g)toB(g) follows first order linetics then the graph of rate of formation (R ) of B against time t will be :

The graph represents the decay of a newly-prepared sample of radioactive nuclide X to a stable nuclide Y. The half-life of X is t. The growth curve for Y intersects the decay curve for X after time T. What is the time T ?

A radioactive element X with half life 2 h decays giving a stable element Y. After a time t, ratio of X and Y atoms is 1:16 .Time t is

A radioactive element A with a half-value period of 2 hours decays giving a stable element Y . After a time t the ratio of X and Y atoms is 1 : 7 then t is :

How can be rate of reaction at a specific in the be determined from a graph of concentration against time ?

Graph of rate of cooling against time is (assume Newton's law of cooling)

Nuclei of a radioactive element X are being produced at a constant rate K and this element decays to a stable nucleus Y with a decay constant lambda and half-life T_(1//3) . At the time t=0 , there are N_(0) nuclei of the element X. The number N_(Y) of nuclei of Y at time t is .