A ball of mass "100g" is moving with "100m/sec" . The wavelength is (A) `6.625times10^(-28)m` (B) `6.625times10^(-35)m` (C) `6.625times10^(-30)m` (D) `6.625times10^(-24)m`

6. ^(*) The current in a metal wire of cross-sectional area 10^(-6)m^(2) is 1.6A .If the free electron density of the metal is 8times 10^(28)m^(-3) then the drift speed of electrons is (A) 1.25times10^(-3)ms^(-1) (B) 2times10^(-3)ms^(-1) (C) 1.25times10^(-4)ms^(-1) (D) 2times10^(-4)ms^(-1)

6. ^(*) The current in a metal wire of cross-sectional area 10^(-6)m^(2) is 1.6A .If the free electron density of the metal is 8times x^(2) x 10^(28)m^(-3) then the drift speed of electrons is (A) 1.25times10^(-3)ms^(-1) (B) 2times10^(-3)ms^(-1) (C) 1.25times10^(-4)ms^(-1) (D) 2times10^(-4)ms^(-1)

A body of mass x kg is moving with a velocity of 100ms^(-1) . Its de-Broglie wavelength is 6.62xx10^(-35)m . Hence, x is: (h=6.62xx10^(-34)Js)

[" 8.The dielectric strength of the air is about "-],[[" (A) "3times10^(6)v/m" (B) "3times10^(4)v/m],[" (C) "3times10^(2)v/m," (D) "3times10^(3)v/m]]

A body of mass x kg is moving with a velocity of 100 ms^(-1) . Its de-Broglie wavelength is 6.62 xx 10^(-35)m . Hence x is (h = 6.02 xx 10^(-34) J s)

A 200 g golf ball is moving with a speed of 5 m per hour. The associated wavelength is ( h=6.625xx10^(-34) J -sec) of the order of

The mass of photon moving with the velocity of 3 xx 10^(8)m//sec with wave length 3.6 A^(@) is

The wavelength associated with a ball of mass 100g moving with a speed of 10^(3) cm sec^(-1) (h=6.6 xx 10^(-34)Js) is:

A body of mass 100g moves at the speed of 36 km/hr. The de Broglie wavelength related to it is of the order………..m (h=6.626 xx 10^(-34) Js)

The momentum of a particle having a de-Broglie wavelength of 10^(17) m is (Given, h=6.625xx10^(-34)m )