The sum of the first 3 terms of a G.P is 16 and sum of next 3 terms of the same GP is 128 ,then value of `((r)/(4)+1)` is where r= common ratio.

The sum of the first 3 terms of a G.P is 16 and sum of next 3 terms of the same G.P is 128 ,then value of ( r/4 + 1 ) is where r = common ratio.

The sum of first three terms of a G.P. is 15 and sum of next three terms is 120. Find the sum of first n terms.

The sum of first three terms of a G.P. is 21 and sum of their squares is 189. Find the common ratio :

The sum of first three terms of a G.P is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.

The sum of first three terms of a G.P.is 16 and the sum of the next three terms is 128. Determine the first term,the common ratio and the sum to n terms of the GP.

The sum of first 6 terms of a G.P. is nine times the sum of the first 3 terms. Find the common ratio.

The sum of the first eight terms of a G.P. is five xx the sum of the first four terms; then the common ratio is

The sum of first two terms of a G.P. is 5/3 and the sum to infinity of the series is 3. Find the first term :