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The probability that when 12 distinct ba...

The probability that when 12 distinct balls are distributed among three distinct boxes, the first will contain exactly three balls is
(A) `(2^(9))/(3^(12))` (B) `(^(12)C_(3)*2^(9))/(9^(6))` (C) `(^(12)C_(3)*2^(12))/(3^(12))` (D) `(^(12)C_(3)*3^(9))/(3^(12))`

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If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

(16xx32)/(9xx27xx81)=?((2)/(3))^(9)b*((2)/(3))^(11)c((2)/(3))^(12)d*((2)/(3))^(13)

Evaluate: (i) .^(12)C_(1)+.^(12)C_(2)+.^(12)C_(3)+ . . .+.^(12)C_(12) (ii) .^(19)C_(3)+.^(19)C_(5)+.^(19)C_(7)+ . . .+^(19)C_(19) .

12(1)/(3)-(8)/(9)+(11)/(3)-4(11)/(9)=?