The minimum value of `logx/x` in the interval `[2,oo)` is (i) `log2/2` (ii)`0` (iii)`1/e` (iv) does not exist

Find the greatest value of x^2 log x in the interval [1,e]

Maximum value of (log x)/(x) in [2,oo)(i)(log2)/(2) (ii) 0( iii) (1)/(e)(iv)1

Lt_(x to (3)/(2))[x] is equal to (i) 1 (ii) -1 (iii) 2 (iv) does not exist

Lt_(x to 0)(|x|)/(x) is equal to (i) 1 (ii) -1 (iii) 0 (iv) does not exist

For x > 1 , the minimum value of 2 log_10(x)-log_x(0.01) is

For x > 1 , the minimum value of 2 log_10(x)-log_x(0.01) is

For x > 1 , the minimum value of 2 log_10(x)-log_x(0.01) is

Consider the equation log_(2)^(2)x-x-4log_(2)x-m^(2)-2m-13=0,m varepsilon R Let the real roots of the equation be x_(1),x_(2), such that x_(1)

If 3^(2 log_3 x)-2x-3=0, then the number of values of 'x' satisfying the equation is (i)0 (ii)1 (iii)2 (iv)more than 2