A line is drawn through a fix point P(`alpha, beta`) to cut the circle `x^2 + y^2 = r^2` at A and B. Then PA.PB is equal to :

A line is drawn through a fixed point P(alpha, B) to cut the circle x^(2)+y^(2)=r^(2) at A and B. Then PA.PB is equal to

A line is drawn through a fix point P(alpha,beta) to cut the circle x^(2)+y^(2)=r^(2) at A and B. Then PAt the circle x^(2)+y^(2)=r^(2) at A and B. Then PAt PB is equal to:

A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

A line drawn through the point P(4,7) cuts the circle x^(2)+y^(2)=9 at the points A and B .Then PA.PB is equal to:

A line passes through the point P (5,6) outside the circle x^(2) + y ^(2) = 12 and meets the circle at A and B. The value of PA. PB is equal to

The tangent at the point (alpha, beta) to the circle x^2 + y^2 = r^2 cuts the axes of coordinates in A and B . Prove that the area of the triangle OAB is a/2 r^4/|alphabeta|, O being the origin.

If a line passes through the point P(1,-2) and cuts the x^2+y^2-x-y= 0at A and B, then themaximum of PA+PB is

A line passing through the points A(1.-2) cuts the circle x^(2)+y^(2)-y=0 at P and Q Then the maximum value of |AP-AQ| is