If one end of the diameter is (1, 1) and the other end lies on the line `x+y=3` , then find the locus of the center of the circle.

If one end of the diameter of a circle is (3, 4) which touches the x-axis then the locus of other end of the diameter of the circle is

The equation of radical axis of two circles is x+y=1. One of the circles has the ends ofa diameter at the points (1,-3) and (4,1) and the other passes through the point (1, 2).Find the equating of these circles.

One end of a diameterof a circle is at (2, 3) and the centre is (-2, 5) , find the coordinates of the other end of the diameter.

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. Then find the radius of the circle.

Two vertices of a triangle are (1,3) and (4,7). The orthocentre lies on the line x+y=3 The locus of the third vertex is

The coordinates of one end of a diameter of a circle are (5, -7) . If the coordinates of the centre be (7, 3) find the coordinates of the other end of the diameter.

If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (-2,5), then the coordinates of the other end of the diameter are

If the coordinates of one end of a diameter of a circle are (2,3) and the coordinates of its centre are (-2,5), then the coordinates of the other end of the diameter are (-6,7) (b) (6,-7)( c) (6,7)(d)(-6,-7)

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.