Find the radical center of the circles `x^2+y^2+4x+6y=19 ,x^2+y^2=9,x^2+y^2-2x-4y=5,`

The radical center of the circles x^(2)+y^(2)-4x-6y+5=0 , x^(2)+y^(2)-2x-4y-1=0 , x^(2)+y^(2)-6x-2y=0 .

The radical center of the circles [x^(2)+y^(2)-4x-6y+5=0],[x^(2)+y^(2)-2x-4y-1=0],[x^(2)+y^(2)-6x-2y=0] , [((-7)/(6),(11)/(6))],[((11)/(6),(7)/(6))],[((7)/(6),(11)/(6))]

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

Find the parametric equation of the circles : 3x^2 + 3y^2 + 4x-6y - 4 = 0

Find the centre and radius of the circle 4x^(2) + 4y^(2) + 16y -4x = 19.

If r_(1), r_(2) " and " r_(3) are the radii of the circle x^(2) + y^(2) - 4x + 6y = 5 , x^(2) + y^(2) + 6x - 4y = 3 " and " x^(2) + y^(2) - 2x + 4y = 8

Find the centre and radius of each of that circles : x^2 +y^2 -4x + 6y=5

Prove that the radii of the circles x^(2)+y^(2)=1,x^(2)+y^(2)-2x-6y=6andx^(2)+y^(2)-4x-12y=9 are in AP.