Find the condition that the circle `(x-3)^2+(y-4)^2=r^2` lies entirely within the circle `x^2+y^2=R^2` .

If the circle (x-2) ^(2) + (y -3) ^(2)=a ^(2) lies entirely in the circle x ^(2) + y ^(2) =b ^(2), then

The circle (x-r) ^(2) + (y-r) ^(2) =r ^(2) touches

The length of the tangent from any point on the circle to the circle (x-3)^(2)+(y+2)^(2)=5r^(2) to the circle (x-3)^(2)+(y+2)^(2)=r^(2) is 4 units.Then the area between the circles is

Find the equation of the circle passing through the centre of the circle x^2 +y^2 -4x-6y=8 and being concentric with the circle x^2 +y^2 - 2x-8y=5 .

Find the point of intersection of the circle x^(2)+y^(2)-3x-4y+2=0 with the x -axis.

If the length of the tengent from any point on the circle x-3^2+y+2^2= 5r^2 to the circle x-3^2+y+2^2 = r^2 is 16 unit,then the area between the two circles in sq unit is

The parametric equation of the circle x^(2)+y^(2)=r^(2) are

The centre of the circle (x-a)^(2)+(y-3)^(2)=9 lies on the straight line x=y and the circle touches the circle x^(2)+y^(2)=1 externally.What are the values of alpha,beta?

If the chord of contact of the tangents from the point (alpha, beta) to the circle x^(2)+y^(2)=r_(1)^(2) is a tangent to the circle (x-a)^(2)+(y-b)^(2)=r_(2)^(2) , then