If one end of the a diameter of the circle `2x^2+2y^2-4x-8y+2=0` is (3, 2), then find the other end of the diameter.

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (-1,2), then the other end of the diameter is

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), the other end is

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2)+y^(2)-4x-6y+11=0 is (3, 4), then find the coordinates of the other end of the diameter.

Find the diameter of the circle 2x^(2)+2y^(2)-6x-9=0 .

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.