Let `C_1` and `C_2` be two circles whose equations are `x^2+y^2-2x=0` and `x^2+y^2+2x=0` and `P(lambda, lambda)` is a variable point

2x^(2)+2y^(2)+4 lambda x+lambda=0 represents a circle for

Let C_(1) and C_(2) be the circles x^(2) + y^(2) - 2x - 2y - 2 = 0 and x^(2) + y^(2) - 6x - 6y + 14 = 0 respectively. If P and Q are points of intersection of these circles, then the area (in sq. units ) of the quadrilateral PC_(1) QC_(2) is :

The angle between x^(2)+y^(2)-2x-2y+1=0 and line y=lambda x + 1-lambda , is

2x^(2)+2y^(2)+2 lambda x+lambda^(2)=0 represents a circle for

The equation of the circle which touches the axes of co-ordination and the line ( x)/( 3) +( y )/( 4) =1 and when centre lines in the first quadrant is x^(2)+y^(2) - 2 lambda x - 2lambda y +lambda^(2) =0 , then lambda is equal to :

If the system of equations 2x-3y+4=0,5x-2y-1=0 and 21x-8y+lambda=0 are consistent,then lambda is

If the equation x^(2)+y^(2)+6x-2y+(lambda^(2)+3lambda+12)=0 represent a circle. Then

If (x+y)^(2)=2(x^(2)+y^(2)) and (xy+lambda)^(2)=4,lambda>0, then lambda is equal to

If (x+y)^(2)=2(x^(2)+y^(2)) and (x-y+lambda)^(2)=4,lambda>0 then lambda is equal to