Find the greatest distance of the point `P(10 ,7)` from the circle `x^2+y^2-4x-2y-20=0`

The geometrical mean between the smallest and greatest distance of the point P(10,7) from the circle x^(2)+y^(2)-4x-2y-20=0 is

Statement 1: The least and greatest distances of the point P(10,7) from the circle x^(2)+y^(2)-4x-2y-20=0 are 6 units and 15 units,respectively.Statement 2: A point (x_(1),y_(1)) lies outside the circle S=x^(2)+y^(2)+2gx+2fy+c=0 if S_(1)>0 where S_(1)=x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c

The maximum distance of the point (4,4) from the circle x^2+y2-2x-15=0 is

Find the shortest distance from the point M(-7,2) to the circle x^(2)+y^(2)-10x-14y-151=0

. The shortest distance from the point (2,-7) to circle x^(2)+y^(2)-14x-10y-151=0

Find the equation of the tangent at the point (0,2) to the circle x^2+y^2-4x+2y-8=0

The sum of the minimum distance and the maximum distance from the point (2,2) to the circle x^(2)+y^(2)+4x-10y-7=0 is

The sum of the minimum distance and the maximum distnace from the point (4,-3) to the circle x ^(2) + y^(2) + 4x -10y-7=0 is

Find the distance of the point (1, 2-1) from the plane x -2y + 4z - 10 = 0 .