[" 22.Two years ago a man was five times as old as his son.Two years later his age will be "8],[" years more than three times the age of his son.Find their present age."]

Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son.

Two years ago a father was five times as old as his son. Two years later, his age will be 8 years more than three times the age of the son. Represent this situation algebraically and graphically .

Two years ago,a father was five xx as old as his son.Two years later,his age will be 8 more than three xx the age of the son.Find the present ages of father and son.

Ten years ago, a man was seven times as old as his son. Two years hence, twice his sage will be equal to five times the age of his son. What is the present age of the son? a. 12 years b. 13 years c. 14 years d. 15years

Four years ago, age of a person was 4 times that of his son. Six years later, the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4years more than three times of the age of his son.Find their present ages.

A man is 24 years older than his son. After 2 years, the man's age will be three times that of his son. Find their present ages.

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4 years more than three xx the age of his son.Find their present ages.

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.