" 49."(a)/(x-a)+(b)/(x-b)=(2c)/(x-c)rarr" for "

Solve by factorization: (a)/(x-a)+(b)/(x-b)=(2c)/(x-c)

Find x in terms of a , b and c : (a)/(x - a) + (b)/(x - b) = (2 c)/(x - c) , x - a , b , c

Long-answer type questions (L.A.) (a)/(x-a)+(b)/(x-b)=(2c)/(x-c)(xnea,b,c) .

Solve by factorization: a/(x-a)+b/(x-b)=(2c)/(x-c)

Find x in terms of a,b and c(a)/(x-a)+(b)/(x-b)+(c)/(x-c)=2(c)/(x-c)x!=a,x!=b,x!=c

(x^(4))/((x-a)(x-b)(x-c))=P(x)+(A)/(x-a)+(B)/(x-b)+(C)/(x-c)rArr P(x)=

If the roots of the equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are equal, then a^(2)+b^(2)+c^(2) is equal to

((x-a)(x-b))/((x-c)(x-d))=A/(x-c)-B/(x-d)+C rArr C=

(x^(2)+x+1)/((x-1)(x-2)(x-3))=A/(x-1)+B/(x-2)+C/(x-3) rArr A+C=