The equilibrium constant for the reaction
`A_(2)(g)+B_(2)(g) hArr 2AB(g)`
is `20` at `500K`. The equilibrium constant for the reaction `2AB(g) hArr A_(2)(g)+B_(2)(g)` would be

The equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g) is 256 at 1000 K. The equilibrium constant for the reaction : SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g) is :

If the value for equilibrium constant for the reaction, A_(2)(g)+2B_(2)(g)hArr4C(g) is 2. What is the equilibrium constant for the reaction: 2C(g)hArr1//2A_(2)(g)+B_(2)(g)

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

At a certain temperature, the value of equilibrium constant for the reaction: A_2+2B_2(g) hArr 2AB_2 is 100. What is the equilibrium constant for the reaction. AB_2(g) hArr 1/2A_2 + B_2 ?

The equilibrium constant for the reaction I_2(g) +Cl_2(g) hArr 2ICl(g) at 740 K is 640. What is the equilibrium constant for the reaction ? 2ICl(g) hArr I_2(g)+Cl_2(g) at the same temperature .

The answer to each of the folowing questions is a single digit integar, ranging from 0 to 9. If the correct answers to the question numbers A, B, C and D (say) are 4,0,9 and 2 respectively , then the correct darkening of bubbles should be as shown on the side : Equilibrium constant for the reaction A_(3) (g) + 3 B_(2) (g) hArr 3 AB_(2) (g) " is " 64*0 "Then the equilibrium constant for the reaction " 1/3 A_(3) (g) + B_(2) (g) hArr AB_(2)(g) will be

The equilibrium constant of the reaction SO_2(g)+1/2O_2(g) hArr SO_3(g) "is " 4xx10^(-3) "atm"^(-1//2) . The equilibrium constant of the reaction 2SO_3(g)hArr2SO_(2)(g)+O_(2)(g) would be :