(sec theta)/((19^(2)theta)/(6))d theta

int(sec theta)/(tan^(2)theta)d theta is.

(tan theta)/(sec theta-1)+(tan theta)/(sec theta+1) is equal to 2tan theta(b)2sec theta(c)2cos ec theta(d)2tan theta sec theta

The value of (sec^2 theta)/(cosec^2 theta)+ (cosec^2 theta)/(sec^2 theta)-(sec^2 theta+ cosec^2 theta) is:

(tan theta+sec theta-1)(tan theta+1+sec theta)=(2sin theta)/(1-sin theta)

(1+2sin theta+sin^(2)theta)/(cos^(2)theta)=(sec theta+tan theta)/(sec theta-tan theta)

Prove that (sec theta+cos theta) (sec theta-cos theta)=tan^(2) theta+sin^(2) theta

(sin 2 theta)/(sin theta)-(cos 2 theta)/(cos theta)= A) sec theta B) tan theta C)1 D)2

If theta_(1),theta_(2),theta_(3),theta_(n) are in AP,whose common difference is d, show that sec theta_(1)sec theta_(2)+sec theta_(2)sec theta_(3)+....+sec theta_(n-1)sec theta_(n)=(tan theta_(n)-tan theta_(1))/(sin d)

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

The value of sec^(2)theta+cosec^(2)theta is equal to a) tan^(2)theta+cot^(2)theta b) sec^(2)thetacosec^(2)theta c) sec theta cosectheta d) sin^(2)theta cos^(2)theta