Given that `sin theta=(a)/(b` then `cos theta=`

If sin theta=(a)/(b), then cos theta=?

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

If tan theta=(a)/(b) , find the value of (a sin theta-b cos theta)/(asin theta+b cos theta)

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

If theta be a positive acute angle and tan theta=(a)/(b) , then find the value of (a sin theta-b cos theta)/(a sin theta+b cos theta).

If tan theta=(a)/(b), prove that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))

If tan theta=(a)/(b), show that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))

Given that sin theta+2cos theta=1 then prove that 2sin theta-cos theta=2

If tan theta=a/b then (a sin theta-b cos theta)/(a sin theta+bcos theta)=