Prove that `(d)/(dx){2x tan^(-1)x-log (1+x^(2))}=2 tan^(-1)x.`

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(d)/(dx) {Tan ^(-1) ""(2x)/(1- x ^(2))}=

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(d)/(dx)=(-2x^(2)) =

d/(dx)[tanh^(-1)((2x)/(1+x^2))]=

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(d)/(dx) "" tan^(-1) ((2e^(x))/(1 - e^(2x)))=