" If cot "theta=(15)/(8)quad ((2+2sin theta)(1-sin theta))/((1+cos theta)(2-2cos theta))

If cot theta=(15)/(8), then Evaluate ((2+2sin theta)(1-sin theta))/((1+cos theta)(2-2cos theta))

(sin 2 theta)/(1-cos 2 theta)=cot theta

Prove that: (sin2 theta)/(1-cos2 theta)=cot theta

Prove that sin(2theta)/(1-cos2theta)=cot theta

Given cot theta =(7)/(8) , then evaluate (i) ((1+sin theta )( 1-sin theta ))/( (1+cos theta )(1-cos theta )) " "(ii) cot^2 theta

((sin theta+cos theta)^(2)-1)/(sin theta*cos theta)

If cot theta = (7) /(8) evaluate (i) (( 1 + sin theta ) (1 - sin ) theta ) /((1 + cos theta ) ( 1 - cos ) theta ) (ii) cot ^ 2 theta

(sin theta)/(1+cos theta)+(1+cos theta)/(sin theta)=2cos ec theta

(1+cos 2 theta)/(sin 2 theta)=cot theta

(cos^(2)theta(1-cos theta))/(sin^(2)theta(1-sin theta))=(1+sin theta)/(1+cos theta)