Find the length of intercept, the circle `x^2+y^2+10 x-6y+9=0` makes on the x-axis.

Explanation

To find the length of the intercept that the circle \( x^2 + y^2 + 10x - 6y + 9 = 0 \) makes on the x-axis, we can follow these steps:

### Step 1: Rewrite the circle equation in standard form
The standard form of a circle's equation is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
To convert the given equation into this form, we will complete the square for both \(x\) and \(y\).
...