`(x^(2))/(4)-3xy^(3)+9y^(6)`

If x=4 and y=1, find the value of ((x)/(2)-(y)/(3))((x^(2))/(4)+(xy)/(6)+(y^(2))/(9)) .

If x=4 and y=1, find the value of ((x)/(2)-(y)/(3))((x^(2))/(4)+(xy)/(6)+(y^(2))/(9)) .

Factorise : (x^(2))/9+(xy^(2))/3+(y^(4))/4

Simplify: (x^(3)-y^(3))/(3x^(2)+9xy+6y^(2))xx(x^(2)+2xy+y^(2))/(x^(2)-y^(2))

Add: (i) 3x, 7x (ii) 7y, -9y (iii) 2xy, 5xy, -xy (iv) 3x, 2y (v) 2x^(2), -3x^(2), 7x^(2) (vi) 7xyz, -5xyz, 9xyz, - 8xyz (vii) 6a^(3) , - 4a^(3), 10 a^(3), - 8a^(3) (viii) x^(2) - a^(2), -5x^(2) + 2a^(2), -4x^(2) + 4a^(2)

Add : x^(3) - x^(2)y + 5xy^(2) + y^(3) , -x^(3) - 9xy^(2) + y^(3), 3x^(2)y + 9xy^(2)

Simplify : (x- 2y + 3z ) ( x^(2) + 4y^(2) + 9z^(2) + 2xy + 6yz - 3xz)

The HCF of 4y^(4)x-9y^(2)x^(3) and 4y^(2)x^(2)+6yx^(3) is