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In Delta ABC, AD is the perpendicular b...

In `Delta ABC`, AD is the perpendicular bisector of BC (see Fig. 7.30). Show that `Delta ABC`is an isosceles triangle in which `A B\ =\ A C`.

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Given: `AD` is the perpendicular bisector of BC means `∠ADB = ∠ADC = 90^@` and `BD = DC`
To Prove: `ΔABC` is an isosceles triangle in which `AB = AC`.
In `ΔADC` and `ΔADB`, ...
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