[(1)/(7x)+(1)/(6y)=3],[(1)/(2x)-(1)/(3y)=5]

Solve the following system of equations: (1)/(7x)+(1)/(6y)=3,quad (1)/(2x)-(1)/(3y)=5

Solve the following system of equations: (1)/(5x)+(1)/(6y)=12,quad (1)/(3x)-(3)/(7y)=8,x!=0,y!=0

(6)/(x+y)=(7)/(x-y)+3(1)/(2(x+y))=(1)/(3(x-y))

Solve the following system of equations: 1/(5x)+1/(6y)=12 ,\ \ \ 1/(3x)-3/(7y)=8,\ x!=0,\ y!=0

Show that the lines (x-3)/(1)=(y-5)/(-2)=(z-7)/(1) and (x-1)/(7)=(y-1)/(6)=(z-1)/(7) are skew lines and find the shortest distance between them.

6/(x+y)=7/(x-y)+3 , 1/(2(x+y))=1/(3(x-y))

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .