xdy+2ydx=0" when "x=2,y=1

xdy + 2 ydx = 0 , " when " x=2 , y=1

The solution of the differential equation xdy + ydx= xydx when y(1)=1 is

Let y(x) be a solution of xdy+ydx+y^(2)(xdy-ydx)=0 satisfying y(1)=1. Statement -1 : The range of y(x) has exactly two points. Statement-2 : The constant of integration is zero.

Let y(x) be a solution of xdy+ydx+y^(2)(xdy-ydx)=0 satisfying y(1)=1. Statement -1 : The range of y(x) has exactly two points. Statement-2 : The constant of integration is zero.

The solution of the differential equation ydx -xdy +3 x^2y^2e^x""^3 dx=0 satisfying y=1 when x=1 , is

y ^ (2) (xdy + ydx) + xdy-ydx = 0

xdx+ydy+(xdy-ydx)/(x^(2)+y^(2))=0 , given y=1, when x=1

Solve: xdx+ ydy+ (xdy-ydx)/(x^2+y^2) =0 given y = 1 when x= 1.

Solution of the differential equation y cos backslash(y)/(x)(xdy-ydx)+x sin backslash(y)/(x)(xdy+ydx)=0 which satisfies y(1)=(pi)/(2) is