`(-5)/(13)+?=-1` `8/(13)` (b) `(-8)/(13)` `(-18)/(13)` (d) `(18)/(13)`

Choose the correct option (-5)/(13)+?=-1 (a) 8/(13) (b) (-8)/(13) (c)(-18)/(13) (d) (18)/(13)

Find: ((-8))/(13)+((-4))/(13)

Simplify: 1/(1+(2/3)/(1+2/3+(8/9)/(1-2/3))) . (11)/(13) (b) (13)/(15) (c) (13)/(11) (d) (15)/(13)

(9)/(13)+(-8)/(13)+(4)/(3)+(-5)/(8)

Find : a. 4 (5)/(13)- 3 (7)/(13) + 2 (8)/(13)

Harmonic conjugate of the point (5, 13) with respect to (2,-5) and (3,1) is (1,(13)/5) (b) ((13)/5,1) ((13)/5,7/5) (d) (-7/5,(13)/5)

Re-arrange suitably and find the sum in each of the following: (3)/(5)+(7)/(3)+(9)/(5)+(-13)/(15)+(-7)/(3) (ii) (4)/(13)+(-5)/(8)+(-8)/(13)+(9)/(13)

Solve : ((-5)/(13) + ((-2))/( 13)) + ((- 3)/(8) + (18)/(20))

(-5)/8+(-9)/13=(-9)/13+(-5)/8

Two circles, each having radius 4, have a common tangent given by 3x+2y-6=0 at (2, 0) . Then their centres are : (A) (2+ 5/sqrt(13), 8/sqrt(13)), (2- 5/sqrt(13) , (-8)/sqrt(13)) (B) (2+ 12/sqrt(13), 8/sqrt(13)) , (2- 12/sqrt(13), (-8)/sqrt(13)) (C) (2, 3), (4, 5) (D) none of these