`(1+secA)/secA=(sin^2A)/(1-cosA)`

Prove the following identities,where the angles involved are acute angles for which the expressions are defined. (iv) (1+secA)/(secA)=(sin^(2)A)/(1-cosA)

Prove that (1+secA)/(secA)=(sin^(2)A)/(1-cosA).

Prove the following identities. where the angles involved are acute angles for which the expressions are defined. (1+secA)/(secA)=(sin^(2)A)/(1-cosA) [Hint: Simplify LHS and RHS separately]

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)

Prove that (tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA) .