For a non-equilibrium process `A + B to` Produts the rate is first order with respect to A and second order with respect to B. If 1.0 Mole each of A and B are introduced into a one liter vessel and the intial rate is `1.0 xx 10^(-2)`mol `L^(-1)s^(-1)`, the rate when half of the reaction have been eonsumed is:

For the non-equilibrium process, A + Brarr products, the rate is first order with respect to A and second order with respect to B. If 1.0 mol each of A and B are introduced into a 1 litre vessel,and the initial rate were 1.0xx10^-2 mol/litre sec.The rate (in mol litre^-1 sec^-1 ) when half of the reactants have been used:

For the non-equilibrium process, A + B rarr Product, the rate is first-order w.r.t. A and second order w.r.t. B . If 1.0 mol each of A and B were inrofuced into 1.0 L vessel and the initial rate was 1.0 xx 10^(-2) mol L^(-1) s^(-1) , calculate the rate when half the reactants have been turned into Products.

For the non-equilibrium process, A + B rarr Product, the rate is first-order w.r.t. A and second order w.r.t. B . If 1.0 mol each of A and B were inrofuced into 1.0 L vessel and the initial rate was 1.0 xx 10^(-2) mol L^(-1) s^(-1) , calculate the rate when half the reactants have been turned into Products.

For the non-equilibrium process, A + B rarr Product, the rate is first-order w.r.t. A and second order w.r.t. B . If 1.0 mol each of A and B were inrofuced into 1.0 L vessel and the initial rate was 1.0 xx 10^(-2) mol L^(-1) s^(-1) , calculate the rate when half the reactants have been turned into Products.