" (ii) "(7)/(5)x^(2)=35

Verify the following: (i) (-12)/(5)+(2)/(7)=(2)/(7)+(-12)/(5) (ii) (-5)/(8)+(-9)/(13)= (-9)/(13)+(-5)/(8) (iii) 3+(-7)/(12)=(-7)/(12)+3 (iv) (2)/(-7)+(12)/(-35)=(12)/(-35)+(2)/(-7)

Assertion (A) : (1)/(5)+(1)/(3.5^(3))+(1)/(5.5^(5))+(1)/(7.5^(7))+…(1)/(2)log((3)/(2)) Reason (R ) : If |x| lt 1 then log_(e )((1+x)/(1-x))=2(x+(x^(3))/(3)+(x^(5))/(5)+…)

Simplify: (i) 7/18 + 5/6 , (ii) (-9/25) + 3/5 , (iii) (-8/35) + (-2/7)

Solve: (3x)/(7)-(4)/(35)=(2x)/(5)

(3.5)/(1!)x+(4.6)/(2!)x^(2)+(5.7)/(3!)x^(3)+....=

Solve by factorization: 7x+(3)/(x)=35(3)/(5)

(18)^(3.5)-:(27)^(3.5)xx6^(3.5)=2^(7)3.5b.4.5c.6d.7e. none of these

3-(1)/(2)of(4)/(7)+(5)/(7)xx(14)/(35)=

Simplify (2a^(2)+5a+3)/(2a^(2)+7a+6)÷(a^(2)+6a+5)/(-5a^(2)-35a-50)