the ratio of potential gradients is `1:2`, the resistance of two potentiometer wires of same length are `2Omega&4Omega` respectively. The current flowing through them are in the ratio

The ratio of potential gradients is 1:2 , the resistance of two potentiometer wires of same length are 2Omega and 4Omega respectively. The current flowing through them are in the ratio

As is the cross sectional area and rho is the specific resistance of a potentiometer wire. If I is the current passing through the potentiometer wire, then the potential gradient along the length of the wire is given by

The resistance of a conductor is twice than another. What will be the ratio of current flow through them under same potential difference.

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is

A 2 V battery, a 990Omega resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is 10Omega , then the potential gradient of the potentiometer wire is

A 2 V battery, a 990Omega resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is 10Omega , then the potential gradient of the potentiometer wire is

A 2 V battery, a 990Omega resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is 10Omega , then the potential gradient of the potentiometer wire is