Copper gives two oxides. On heating `1g` of each in hydrogen, we get `0.888 g and 0.798 g` of the metal respectively. Show that these results are in agreement with the Law of Multiple Proportions.

Copper gives two oxides. On heating one gram of each in hydrogen, we get 0.888g and 0.798g of the metal respectively. Show that these results are in agreement with law of multiple proportion.

Copper gives two oxides. On heating 1.0 g of each in hydrogen gas, 0.888 g and 0.799 g of the metal are produced. Show that the results agree with the Law of Multiple Proportions.

1.5 g of each of the two oxides of an element of reduction with hydrogen produced 1.331 g and 1.196g of the element respectively. Show that the result are in agreement with the law of reciprocal proportion.

Two oxides of a metal, M were heated separately in hydrogen. The water obtained in each case were carefully collected and weighed. It was observed that- (1) 0.725g of the first oxide gives 0.18g of water and (2) 2.86g of the second oxide gives 0.36g of water. show that these results are in acccordance with the law of multiple proportions.

metal combines with oxygen to form two oxides, having the following composition: (i) 0.398 g of the first metal oxide contains 0.318g of metal. (ii) 0.716 g of the second oxide contains 0.636g of the metal. Show that the above data agrees with the law of multiple proportions.

metal combines with oxygen to form two oxides, having the following composition: (i) 0.398 g of the first metal oxide contains 0.318g of metal. (ii) 0.716 g of the second oxide contains 0.636g of the metal. Show that the above data agrees with the law of multiple proportions.