" (b) "2x+3y=2,x-2y=8

" (2) "3x+y=-1,2x-3y=-8

3x+2y=8 2x-3y=8

Solve: 2x+3y=2; x-2y=8

(a) 2x+y=5 ; 3x+2y=8

Which of the following line can be tangent to the parabola y^2=8x ? x-y+2=0 (b) 9x-3y+2=0 x+2y+8=0 (d) x+3y+12=0

Which of the following line can be tangent to the parabola y^2=8x ? x-y+2=0 (b) 9x-3y+2=0 x+2y+8=0 (d) x+3y+12=0

2x+3y=8 4x-5y=-6

For hyperbola whose center is at (1, 2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1 , the equation of the hyperbola passing through (2, 4) is (a) (2x+3y-5)(x+2y-8)=40 (b) (2x+3y-8)(x+2y-8)=40 (c) (2x+3y-8)(x+2y-5)=30 (d) none of these

For hyperbola whose center is at (1, 2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1 , the equation of the hyperbola passing through (2, 4) is (a) (2x+3y-5)(x+2y-8)=40 (b) (2x+3y-8)(x+2y-5)=40 (c) (2x+3y-8)(x+2y-5)=30 (d) none of these

For hyperbola whose center is at (1, 2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1 , the equation of the hyperbola passing through (2, 4) is (a) (2x+3y-5)(x+2y-8)=40 (b) (2x+3y-8)(x+2y-5)=40 (c) (2x+3y-8)(x+2y-5)=30 (d) none of these