Home
Class 11
MATHS
From a point P on the normal y=x+c of th...

From a point `P` on the normal `y=x+c` of the circle `x^2+y^2-2x-4y+5-lambda^2-0,` two tangents are drawn to the same circle touching it at point `Ba n dC` . If the area of quadrilateral `O B P C` (where `O` is the center of the circle) is 36 sq. units, find the possible values of `lambdadot` It is given that point `P` is at distance `|lambda|(sqrt(2)-1)` from the circle.

Promotional Banner

Similar Questions

Explore conceptually related problems

Two tangents to the circle x^(2)+y^(2)=4 at the points A and B meet at P(-4,0), The area of the quadrilateral PAOB, where O is the origin,is

Let A be the centre of the circle x^(2)+y^(2)-2x-4y-20=0 . If the tangents at the points B (1, 7) and D(4, -2) on the circle meet at the point C, then the perimeter of the quadrilateral ABCD is

From a point P on the line 2x y 4 which is nearest to the circle x2 ty 12y35 tangents are drawn to give circle.The area of quadrilateral PACB (where 'C' is the center of circle and PA & PB re the tangents.) is

A line y=2x+c intersects the circle x^(2)+y^(2)-2x-4y+1=0 at P and Q. If the tangents at P and Q to the circle intersect at a right angle,then |c| is equal to

If the circle x^(2)+y^(2)-4x-6y+lambda=0 touches the axis of x, then determine the value of lambda and the point of contact

Two tangents are drawn from a point P on the circle at point A and B. O is the centre of the circle. If angleAOP=60^(@) then find angleAPB .

If 'P' is any point on the circumference of the circle x^(2) + y^(2) - 4x - 4y -8 =0 , then the perpendicular distance of the tangent at P from the centre of the circle is