A scooter going due east at `10 ms^(-1)` turns right through an angle of `90^(@)`. If the speed of the scooter remain unchanged in taking turn, the change is the velocity the scooter is

A scooter going towards east at 10 m s^-1 turns right through an angle of 90^@ . If the speed of the scooter remains unchanged in taking tum, the change in the velocity of the scooter is

A scooter is going towards east at 10m/s turns right through an angle of 90^@ . If the second remains unchanged in taking this turn.what is the change in the velocity of scooter ?

A car going due North at 10sqrt(2) ms^(-1) turns right through an angle of 90^(@) without changing speed. The change in velocity of car is

A car is moving on a straight road due north with a uniform speed of 50kmh^(-1) when it turns left through 90^(@). If the speed remains unchanged after turning,the change in the velocity of the car in the turning process is

A car is moving on a straight road due north with a uniform speed of 50 km h^-1 when it turns left through 90^@ . If the speed remains unchanged after turning, the change in the velocity of the car in the turning process is

A bus is moving on a straight road towards north with a uniform speed of 50 km//hour turns through 90^(@) . If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is

A bus is moving on a straight road towards north with a uniform speed of 50 km//hour turns left through 90^(@) . If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is