2x+4y-8xy-1

Evaluate : 3x^(2) + 5xy - 4y^(2) + x^(2) - 8xy - 5y^(2)

What are the factors of x^(2)+4y^(2)+4y-4xy-2x-8 ?

Equation of the rectangular hyperbola whose focus is (1,-1) and the corresponding directrix is x-y+1=0 . a. x^(2)-y^(2)=1 b. xy=1 c. 2xy-4x+4y+1=0 d. 2xy+4x-4y-1=0

The equation oi the conic with focus at (1,-1) directrix along x-y+1=0 and eccentricity sqrt(2) is xy=1 b.2xy+4x-4y-1=0cx^(2)-y^(2)=1 d.2xy-4x+4y=1=0

Add 4x^2-7xy+6y^2, 4x^2+7xy-6y^2, 4xy-8y^2

Add: 4x^(2) - 7xy + 4y^(2) - 3, 5 + 6y^(2) - 8xy + x^(2) and 6 - 2xy + 2x^(2) - 5y^(2)

Show that two pairs of lines 3x^(2)+8xy-3y^(2)=0 and 3x^(2)+8xy-3y^(2)+2x-4y-1=0 forms a square.