`int_(pi/6)^(pi/3) sqrttanx/(sqrttanx+sqrtcotx)dx`

int(sqrttanx+sqrtcotx)dx

Integrate: int_0^(pi/2)(sqrttanx)/(sqrttanx+sqrtcotx)dx

Evaluate the following integrals. int_(theta)^(pi/2)(sqrt(tanx))/(sqrttanx+sqrtcotx)dx

int_0^(pi/2) (sqrtcotx)/(sqrttanx+sqrtcotx) dx is equal to :

int_(pi/6)^(pi/3) (dx)/(1+sqrtcotx) =

I : int_(0)^(pi//2)(sqrtcotx)/(sqrt(tanx)+sqrt(cotx))dx=(pi)/(4) II : int_(0)^(pi//2)(2sinx+3cosx)/(sinx+cosx)dx=(pi)/(4)

int_(pi//6)^(pi//3)dx/(1+sqrtcotx)

int_(pi/6)^( pi/3)sin(3x)dx

int_(pi/3)^(pi/2) sinx dx