`int(cosx-sinx)/((cosx+sinx)dx`

int((2cosx-3sinx)/(3cosx+2sinx))dx

inte^(cosx)(sinxcosx+sinx)dx=

int(x-sinx)/(1-cosx)dx

If int(cosx-sinx)/(8-sin2x)dx=(1)/(p)log[(3+sinx+cosx)/(3-sinx-cosx)]+c , then p= . . . .

int(cosx-sinx)/(1+2sin x cosx)dx is equal to

int(sinx)/((1+cosx))dx

"If " int(2cosx-sinx+lambda)/(cosx+sinx-2)dx=A " In"|cosx+sinx-2|+Bx+C, " then the value of " A+B+|lambda| " is"-.

int(2cosx-sinx)/(3+2sinx+cosx)dx