`int(x^2cosx)/(1+sinx)^2dx`

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Evaluate: underset(0)overset(pi)int(x^2cosx)/((1+sinx)^2)dx

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int(cosx)/((1+sinx)(2+sinx))dx

int(cos^(2)x)/(1+sinx)dx+int(sin^(2)x)/(1-cosx)dx=

int(cosx)/((1+sinx)(2+sin x))dx

I=int (sinx+cosx)/sqrt(1-sin2x) dx