Home
Class 11
MATHS
The equation of the circumcircle of an e...

The equation of the circumcircle of an equilateral triangle is `x^2+y^2+2gx+2fy+c=0` and one vertex of the triangle in (1, 1). The equation of the incircle of the triangle is `4(x^2+y^2)=g^2+f^2` `4(x^2+y^2)=8gx+8fy=(1-g)(1+3g)+(1-f)(1+3f)` `4(x^2+y^2)=8gx+8fy=g^2+f^2` `non eoft h e s e`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the area of equilateral triangle inscribed in a circle x^(2)+y^(2)+2gx+2fy+c=0

Tangents OP and OQ are drawn from the origin O to the circle x^(2) +y^(2) + 2gx + 2fy +c =0 . Then the equation of the circumcircle of the triangle OPQ is :

The order of the differential equation whose solution is x^(2)+y^(2)+2gx+2fy+c=0 is

The centre of the circle that cuts the circle x^(2)+y^(2)+2gx+2fy+c=0 and lines x=g and y=f orthogonally is

The equation of the normal at P(x_(1),y_(1)) to the circle x^(2)+y^(2)+2gx+2fy+c=0 is

Tangents OP and OQ are drawn from the origin o to the circle x^(2)+y^(2)+2gx+2fy+c=0. Find the equation of the circumcircle of the triangle OPQ.

If the circle x ^(2) + y^(2) + 2gx + 2fy+ c=0 touches X-axis, then