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x=2at^(2),y=at^(4)...

`x=2at^(2),y=at^(4)`

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Find (dy)/(dx) in the following x = 2 at^2 ,y = at^4

Factorise : x^(4) + x^(2)y^(2) + y^(4)

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Solve (x+y(dy)/(dx))/(y-x(dy)/(dx))=x^(2)+2y^(2)+(y^(4))/(x^(2))

The locus of the middle points of the portions of the tangents of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 included between the axis is the curve (a) (x^(2))/(a^(2))+(y^(2))/(b^(2))=(1)/(4) (b) quad (a^(2))/(x^(2))+(b^(2))/(y^(2))=4 (c) a^(2)x^(2)+b^(2)y^(2)=4 (d) b^(2)x^(2)+a^(2)y^(2)=4