`A B` and `C D` are two parallel lines. `P Q` cuts `A B\ a n d\ C D` at `E\ a n d\ F` respectively. `E L` is the bisector of `/_F E Bdot` If `/_L E B=35^0,` then `/_C F Q` will be `55^0` (b) `70^0` (c) `110^0` (d) `130^0`

In Figure, A B=A CdotB E\ a n d\ C F are respectively the bisectors of /_B and /_C . Prove that E C B \ ~=\ F C B

In A B C , /_B=/_C and ray A X bisects the exterior angle /_D A CdotIf /_D A X=70^0, t h e n /_A C B= 35^0 (b) 90^0 (c) 70^0 (d) 55^0

In a A B C ,\ /_A=50^0a n d\ B C is produced to a point Ddot If the bisectors of /_A B C\ a n d\ /_A C D meet at E , then /_E= (a) 25^0 (b) 50^0 (c) 100^0 (d) 75^0

Line segments A B\ a n d\ C D intersect at O such that A C = D Bdot If /_C A B=45^0a n d\ /_C D B=55^0, then /_B O D= (a) 100^0 (b) 80^0 (c) 90^0 (d) 135^0

In A B C ,\ /_B=/_C and ray A X bisects the exterior angle /_D A CdotIf\ /_D A X=70^0,\ t h e n\ /_A C B= (a) 35^0 (b) 90^0 (c) 70^0 (d) 55^0

In Figure, A B\ a n d\ C D are parallel lines and transversal E F intersects them at P\ a n d\ Q respectively. If /_A P R=25^0,\ /_R Q C=30^0a n d\ /_C Q F=65^0, then (a) x=55^0,\ y=40^0 (b) x=50^0,\ y=45^0 (c) x=60^0,\ y=35^0 (d) x=35^0,\ y=60^0

In Figure, if A E||D C and A B=A C , the value of /_A B D is 70^0 (b) 110^0 (c) 120^0 (d) 130^0

Line segments A B a n d C D intersect at O such that A C D Bdot If /_C A B=45^0a n d /_C D B=55^0, then /_B O D= 100^0 (b) 80^0 (c) 90^0 (d) 135^0

In Figure, if E C A B , /_E C D=70^0A N D /_B D O=20^0 , then /_O B D is: 20^0 (b) 50^0 (c) 60^0 (d) 70^0

In Figure, A B a n d C D are parallel lines and transversal E F intersects them at P a n d Q respectively. If /_A P R=25^0, /_R Q C=30^0a n d /_C Q F=65^0, then x=55^0, y=44^0 (b) x=55^0, y=45^0 x=60^0, y=35^0 (d) x=35^0, y=60^0