The length of a simple pendulum is `1 m`. The bob is given a velocity `7 ms^(-1)` in horizontal direction from mean position. During upward motion of bob, if the string breaks when the bob is horizontal, then the maximum vertical height of ascent of bob from rest position is

The energy of a bob of simple pendulum at mean position is purely________.

Mass of the bob of a simple pendulum of length L is m . If the bob is projected horizontally from its mean position with velocity sqrt(4 gL) , then the tension in the string becomes zero after a vertical displacement of

A simple pendulum is released from rest with the string in horizontal position. The vertical component of the velocity of the bob becomes maximum, when the string makes an angle theta with the vertical. The angle theta is equal to

A simple pendulum is released from rest with the string in horizontal position. The vertical component of the velocity of the bob becomes maximum, when the string makes an angle theta with the vertical. The angle theta is equal to

A simple pendulam of length .l. carries a bob of mass .m.. The bob is released from horizontal position. The tension in the string at t he lowest point would be

The bob of a simple pendulum of length L, is displaced through 90^(@) , from its mean position and then released. What will be the tension in the string when the bob of mass m will be its lowest position ?

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60^(@) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

In a simple pendulum, the breaking strength of the string is double the weight of the bob. The bob is released from rest when the string is horizontal. The string breaks when it makes an angle theta with the vertical.