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Find cot 48^@times cot16^@times cot42^@t...

Find `cot 48^@times cot16^@times cot42^@times cot74^(@)`

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sec16^(@)cos74^(@)-cot74^(@)tan16^(@)

cot6^(0)cot42^(0)cot66^(@)cot78^(@)=1

The value of cot 15^(@) cot 16^(@) cot 17^(@) . . . . . cot 73^(@) cot 74^(@) cot 75^(@) is :

cot 16^(@) cot 44^(@) + cot 44^(@) cot 76^(@) - cot 76^(@) cot 16^(@)=

cot 6^0 cot 42^0 cot 66^0 cot 78^0=1

Show that, cot16^(@) cot44^(@) + cot44^(@) cot76^(@) + cot76^(@) cot 16^(@) = 3