Two capacitors of equal capacitance when connected in series hae net capacitance `C_(1)` and when connected in parallel have net capacitance `C_(2)` what is the value of `C_(1)//C_(2)`?

Three capacitors of equal capacitance, when connected in series have net capacitance C_(1) , and when connected in parallel have net capacitance C_(2) . What is the value of C_(1)//C_(2) ?

Three capacitors of equal capacitance, when connected in series, have a net capacitance C_1 . When connected in parallel, they have a net capacitance C_2 . What is the value of (C_1)/(C_2) ?

Three capacitors of equal capacitance, when connected in series, have a net capacitance of C_1 and when connected in parallel, have a capacitance of C_2 what will be the value of C_1//C_2 ?

Five equal capacitors are connected in series and have net capacitance C_1 and when connected in parallel, they have capacitance C_2 . The value of C_1/C_2 :

Four capacitors of equal capacitance have a net capacitance C_(1) when connected in series and a net capacitance C_(2) when connected in parallel. The ratio of C_(1)//C_(2) is

Four capacitors of equal capacitance have an equivalent capacitance C_(1) when connected in series and an equivalent capacitance C_(2) when connected in parallel. The ratio (C_(1))/(C_(2)) is

Four capacitors of equal capacitance have an equivalent capacitance C_(1) when connected in series and an equivalent capacitance C_(2) when connected in parallel. The ratio (C_(1))/(C_(2)) is

When a number of capcitors of equal capacitances are connected in series, the effective capacitance is 0.4 mu F and when they are connected in parallel, the effective capacitance is 90mu F . What is the capacitance of each capacitor ?

n idential capacitors each of capacitance C when connected in series give equivalent capacitance 1.2muF and when connect in parallel give 120muF . Then n and C are

Two capacitors have a capacitance of 5 muF when connected in parallel and 1.2 muF when connected in series. Calculate their capacitance.