Home
Class 11
CHEMISTRY
In the organic compound CH(2) = CH – CH(...

In the organic compound `CH_(2) = CH – CH_(2) – CH_(2) – C equivCH`, the pair of hydridised orbitals involved in the formation of: `C_(2) – C_(3)` bond is:
`(a) sp – sp_(2) (b) sp – sp_(3) (c) sp_(2 )– sp_(3) (d) sp_(3) – sp_(3)`

Promotional Banner

Similar Questions

Explore conceptually related problems

In the organic compound CH_(2)=CH-CH_(2)-CH_(2)-C-=CH , the pair of hydridised orbitals involved in the formation of: C_(2) – C_(3) bond is: (a) sp-sp^(2) (b) sp-sp^(3) (c ) sp^(2)-sp^(3) (d) sp^(3)-sp^(3)

The type of hybridisation of boron in diborane is (a) sp , (b) sp^(2) , (c) sp^(3) , (d) dsp^(2)

The type of hybridisation of boron in diborane is (a) sp , (b) sp^(2) , (c) sp^(3) , (d) dsp^(2)

The type of hybridisation of boron in diborane is (a) sp , (b) sp^(2) , (c) sp^(3) , (d) dsp^(2)

Consider the compound given below H_(2)C = CH - CH = CH - CH_(2) - OH The number of sp^(3) hybridised atoms are