If one of the diameters of the circle `x^2+y^2-2x-6y+ 6 = 0` is a chord to the circle with centre (2, 1), then the radius of circle is:

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with center (2,1) ,then the radius of the circle is

If one of the diameters of the curve ""^(2) + y ^(2) - 4x - 6y +9=0 is a chord of a circle with centre (1,1) then the radius of this circel is

Diameter of x^2+y^2-2x-6y+6=0 is chord of circle with center (2,1) then radius of bigger circle is

One of the diameters of the circle x^(2)+y^(2)-12x+4y+6=0 is given by

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

If one of the diameters of the circle,given by the equation,x^(2)+y^(2)-4x+6y-12=0 is a chord of a circle S,whose centre is at (-3,2), then the radius of s is :

If one of the diameter of the circle, given by the equation x^(2)+y^(2)+4x+6y-12=0 , is a chord of a circle S, whose centre is (2,-3), the radius of S is