Statement 1 : The center of the circle having `x+y=3` and `x-y=1` as its normals is (1, 2) Statement 2 : The normals to the circle always pass through its center

Statement I The line 3x-4y=7 is a diameter of the circle x^(2)+y^(2)-2x+2y-47=0 Statement II Normal of a circle always pass through centre of circle

The normal to the circle x^(2) + y^(2) -2x -2y = 0 passing through (2,2) is

The equation of the circle having the lines y^(2)-2y+4x-2xy=0 as its normals &x passing through the point (2,1) is.

Find the center of the circle x=-1+2cos theta,y=3+2sin theta

Find the center of the circle x=-1+2cos theta,y=3+2sin theta

Statement 1: The line x-y-5=0 cannot be normal to the parabola (5x-15)^(2)+(5y+10)^(2)=(3x-4y+2)^(2) Statement 2: Normal to parabola never passes through its focus.

Statement 1 : Let S_1: x^2+y^2-10 x-12 y-39=0, S_2 x^2+y^2-2x-4y+1=0 and S_3:2x^2+2y^2-20 x=24 y+78=0. The radical center of these circles taken pairwise is (-2,-3)dot Statement 2 : The point of intersection of three radical axes of three circles taken in pairs is known as the radical center.

The equation of the circle having the lines y^(2) – 2y + 4x – 2xy = 0 as its normals & passing through the point (2, 1) is

The radius of the circle passing through the point (6,2) and having x+y=6 as its normal and x+2y=4 as its diameter is :