cosx + secx = 2...

`cosx + secx = 2`

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Find the number of solutions of tanx + secx = 2cosx in [0,2pi]

(i) sinx=(sqrt(3))/(2) (ii) cosx=1 (iii) secx=sqrt(2)

Number of solutions of equation for tanx + secx =2cosx in interval [0,2pi]

If y=(sinx)^(tanx)+(cosx)^(secx) , find (dy)/(dx)

If y=(sin x)^(tan x)+ (cosx) ^(secx) ,then (dy)/(dx)

If y=(sinx)^(tanx)+(cosx)^(secx) , find (dy)/(dx)

int(1)/(cosx+secx)dx=

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