(10.3times10/3times10.3+11)/(10.3times10.3-10.3+1)~~000times00

Solve: 21.3times10

root(3)(6.11times0.11times0.11times10.648)

(10.3 xx 10.3 xx 10.3 +1)/(10.3 xx 10.3 - 10.3 + 1) is equal to

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)

There are 10 turns in coil M and 15 turns in coil N .If a current of 2A is passed through coil M then the flux linked with coil N is 1.8times10^(-3)Wb .If a current of 3A is passed through coil N then flux linked with coil M is : (A) 1.2times10^(-3)Wb (B) 2.7times10^(-3)Wb (C) 1.8times10^(-3)Wb (D) 4.05times10^(-3)Wb

[" 8.The dielectric strength of the air is about "-],[[" (A) "3times10^(6)v/m" (B) "3times10^(4)v/m],[" (C) "3times10^(2)v/m," (D) "3times10^(3)v/m]]

(3^(-7)-:3^(-10))times3^(-5)

[" Four charges "10^(-3):-2times10^(-5);+3times10^(-5)" and "],[2times10^(-5)" coulomb are placed at the four "],[" corners of a square of side "1m" the potential "],[" at the centre of the square is "]

(-10)xx(3) =

(6)/(11)+(3)/(8)-:(33)/(44)times(10)/(11)